A) \[-121\text{ }kJ\text{ }mo{{l}^{-1}}\]
B) \[+121\text{ }kJ\text{ }mo{{l}^{-1}}\]
C) \[-242\text{ }kJ\text{ }mo{{l}^{-1}}\]
D) \[+242\text{ kJ mo}{{\text{l}}^{-1}}\]
Correct Answer: A
Solution :
\[\Delta H=\sum{{{(\Delta {{H}_{combustion}})}_{\operatorname{Re}ac\tan t}}-\sum{{{(\Delta {{H}_{combusion}})}_{\Pr oduct}}}}\] \[=(-3800-241)-(-3920)=-121kJ\,mo{{l}^{-1}}\]
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