A) zero
B) 0.5
C) 1.0
D) depends on values of L,C and R
Correct Answer: C
Solution :
Key Idea: At resonance voltage and current are in phase. Average power of circuit is giver; as:- \[P={{E}_{rms}}\times {{i}_{rms}}\times \cos \phi .\] where \[{{E}_{rms}}\] and \[{{i}_{rms}}\]are root mean square value of voltage and current and \[\cos \phi \] is power factor. In a series L-C-R circuit at resonance voltage and current being in same phase hence \[\phi =0\]. Therefore, power factor \[=\cos \phi \] \[\Rightarrow \] \[\cos \,{{0}^{o}}=1\]
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