A) \[\mu ={{r}_{p}}\times gm\]
B) \[{{r}_{p}}=\mu \times gm\]
C) \[gm=\mu \times {{r}_{p}}\]
D) none of these.
Correct Answer: A
Solution :
From the formula the amplification factor \[(\mu )\] is \[\mu ={{\left( \frac{\Delta {{V}_{p}}}{\Delta {{V}_{g}}} \right)}_{ip}}=\] constant .....(i) Where \[\Delta {{V}_{p}}\] is the change in plate voltage and \[\Delta {{V}_{g}}\]the change in grid voltage \[{{r}_{p}}={{\left( \frac{\Delta {{V}_{p}}}{\Delta {{i}_{p}}} \right)}_{{{\upsilon }_{g}}}}\] constant ...(ii) Trans conductance is given by \[{{g}_{m}}={{\left( \frac{\Delta {{i}_{p}}}{\Delta {{\upsilon }_{p}}} \right)}_{{{\upsilon }_{g}}}}=\] constant ...(iii) \[\Rightarrow \] \[\mu =\frac{\Delta {{V}_{p}}}{\Delta {{V}_{g}}}=\frac{\Delta {{V}_{p}}}{\Delta {{i}_{p}}}\times \frac{\Delta {{i}_{p}}}{{{\Delta }_{{{\upsilon }_{g}}}}}\] From equations (ii) and (iii), we get: \[\mu ={{r}_{p}}\times {{g}_{m}}\]You need to login to perform this action.
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