A) \[\frac{1}{3}S\]
B) \[\frac{1}{4}S\]
C) \[\frac{2}{3}S\]
D) \[\frac{1}{6}S\]
Correct Answer: A
Solution :
The displacement equation of SHM is \[y=a\,\sin \omega t'\] Where co is angular velocity \[\left( \omega =\frac{2\pi }{T} \right)\] and a the amplitude Here, \[y=\frac{9}{2},\,t'=\frac{t}{4}\] \[\frac{a}{2}=a\,\sin \frac{2\pi t}{4}\] or \[\frac{1}{2}=\,\sin \frac{\pi t}{2}\] \[\therefore \] \[\sin \frac{\pi }{6}=\sin \frac{\pi t}{2}\] or \[\frac{\pi }{6}=\frac{\pi t}{2}\] or \[t=\frac{1}{3}S.\]You need to login to perform this action.
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