A) \[\left( \frac{3}{7} \right)R\,\Omega \]
B) \[\left( \frac{7}{3} \right)R\,\Omega \]
C) \[\left( \frac{9}{8} \right)R\,\Omega \]
D) \[\left( \frac{8}{9} \right)R\,\Omega \]
Correct Answer: B
Solution :
From figure first three resistance are connected in parallel. \[\Rightarrow \] \[\frac{1}{{{R}_{P}}}=\frac{1}{R}+\frac{1}{R}+\frac{1}{R}+\frac{1}{R}=\frac{3}{R}\] \[\Rightarrow \] \[{{R}_{P}}=\frac{R}{3}\Omega \] Now, the reduced diagram will be. All the resistance are connected in series. \[\therefore \] \[{{R}_{eff}}=\frac{R}{3}+R+R=\frac{R}{3}+2\Omega \] \[\Rightarrow \] \[{{R}_{eff}}=\frac{7R}{3}\Omega .\]You need to login to perform this action.
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