A) \[\frac{10}{\sqrt{2}}A\]
B) \[\frac{5}{\sqrt{2}}A\]
C) \[20\sqrt{2}A\]
D) \[10\sqrt{2}A\]
Correct Answer: D
Solution :
Ammeter reads the roots mean square value of current \[({{i}_{rms}})\]and \[{{i}_{rms}}\] is given by \[{{i}_{rms}}=\frac{{{i}_{0}}}{\sqrt{2}}\] Where, \[{{i}_{0}}=\]peak value of current \[{{i}_{0}}=\sqrt{2}\times {{i}_{rms}}\] Here, \[{{i}_{rms}}=10A\] \[{{i}_{0}}=\sqrt{2}\times 10A=10\sqrt{2}A.\]
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