A) 32 volt
B) 18 volt
C) 19 volt
D) 16 volt
Correct Answer: D
Solution :
From the formula e.m.f. \[=\frac{d\phi }{dt}\] Here, \[\phi =3{{t}^{2}}+4t+2\] .....(i) Differentiating equation (ii) \[\phi \] with respect to we get \[\frac{d\phi }{dt}=\frac{3d}{dt}({{t}^{2}})+4\frac{d}{dt}(t)+\frac{d}{dt}\] (2) \[\frac{d\phi }{dt}=6t+4\] \[\left( \because \,\,\frac{d}{dt}{{t}^{n}}=n{{t}^{n-1}} \right)\] \[\Rightarrow \] \[{{\left[ \frac{d\phi }{dt} \right]}_{t-2}}=16\,volt\]
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