A) \[N{{O}^{-}}\]
B) \[N{{O}^{+}}\]
C) \[C{{N}^{-}}\]
D) \[{{N}_{2}}\]
Correct Answer: A
Solution :
The bond order of \[CO\]is 3. \[N{{O}^{+}},C{{N}^{-}}\] and \[{{N}_{2}}\] are isoelectronic with \[CO\]hence they have the same bond order as \[CO\]. \[N{{O}^{-}}(16{{e}^{-}})\] has bond order of 2.You need to login to perform this action.
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