A) 0.383 mm
B) 23-1 min
C) 8.73 mm
D) 7.53 mm
Correct Answer: B
Solution :
Rate\[=K{{[A]}^{1}}\] \[K=\frac{1.5\times {{10}^{-2}}}{0.5}\,{{\min }^{-1}}\] \[\therefore \]\[{{t}_{1/2}}=\frac{0.693}{K}=\frac{0.693\times 0.5}{1.5\times {{10}^{-2}}}=23.1\,\min \] A 1.3 y. 1UYou need to login to perform this action.
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