A player caught a cricket ball of mass 150 gm moving at a rate of 20 m/s. If the catching process be completed in 0.1 s, then the force of the blow exerted by the ball on the hands of the player is
A) 0.3 N
B) 30 N
C) 300 N
D) 3000 N
Correct Answer:
B
Solution :
Force exerted by the ball on hands of player \[=\frac{mdv}{dt}=\frac{0.15\times 20}{0.1}=30\,N\]