A) \[0.29\text{ }g/ml\]
B) 1.40g/ml
C) 2.81 g/ml
D) 3.41 g/ml
Correct Answer: D
Solution :
Given \[P=5.00\,atm,R=0.0821\,atm\,{{K}^{-1}}\,mo{{l}^{-1}}\] \[T=227+273=500\,K,\,<{{M}_{{{N}_{2}}}}=28\] Density \[=\frac{PM}{RT}=\frac{5\times 28}{0.0821\times 500}=3.41\,g/ml\]You need to login to perform this action.
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