A) \[1.0\times {{10}^{-10}}\]
B) \[1.0\times {{10}^{-8}}\]
C) \[1.0\times {{10}^{-16}}\]
D) \[1.0\times {{10}^{-12}}\]
Correct Answer: A
Solution :
For \[HI\rightleftharpoons \frac{1}{2}{{H}_{2}}+\frac{1}{2}{{I}_{2}};{{K}_{{{C}_{1}}}}=8\] Reverse given eqn. and multiply by 2. \[\therefore \] For \[{{H}_{2}}+{{I}_{2}}\rightleftharpoons 2HI;\,{{K}_{{{C}_{2}}}}={{\left( \frac{1}{{{K}_{{{c}_{1}}}}} \right)}^{2}}\] \[={{\left( \frac{1}{8} \right)}^{2}}=\frac{1}{64}\]You need to login to perform this action.
You will be redirected in
3 sec