A) \[C{{H}_{3}}CH=C{{H}_{2}}\]
B) \[C{{H}_{3}}-C\equiv C{{H}_{2}}\]
C)
D)
Correct Answer: B
Solution :
\[C{{H}_{3}}C{{H}_{2}}CHC{{l}_{2}}\xrightarrow[-HCl]{NaN{{H}_{2}}}C{{H}_{3}}CH=CHCl\] \[\xrightarrow[-HCl]{NaN{{H}_{2}}}C{{H}_{3}}C\equiv CH\]You need to login to perform this action.
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