A) \[0.5\,\pi \]
B) \[\pi \]
C) \[0.707\pi \]
D) zero
Correct Answer: A
Solution :
The displacement equation of particle executing SHM is \[x=a\cos \,\omega t\] (i) Velocity, \[v=\frac{dx}{dt}=-a\omega \sin \omega t\] (ii) and its acceleration, \[a=\frac{dv}{dt}=-a{{\omega }^{2}}\cos \omega t\] (iii) and its acceleration, Fig. (i) shows a plot of Eq. (i). Fig. (ii) shows Eq. (ii) and Fig (iii) is a plot of Eq. (iii). It should be noted that in the figures the curve of v is shifted (to the left) from the curve of\[x\]by one-quarter period \[\left( \frac{1}{4}T \right).\]You need to login to perform this action.
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