A) 1.732 M
B) 3 M
C) \[1.02\times {{10}^{-4}}\,M\]
D) \[3.5\times {{10}^{5}}M\]
Correct Answer: B
Solution :
\[r=K[{{N}_{2}}{{O}_{5}}]\] \[\therefore \] \[[{{N}_{2}}{{O}_{5}}]=\frac{r}{K}=\frac{1.02\times {{10}^{-4}}}{3.4\times {{10}^{-5}}}=\,3\,M\]You need to login to perform this action.
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