NEET Sample Paper NEET Sample Test Paper-37

  • question_answer
    The position vector of a particle \[\vec{R}\]as a function of time is given by: \[\vec{R}=4\sin (2\pi t)\hat{i}+4\cos (2\pi t)\hat{j}\] Where R is in meters, \[t\]is in seconds and \[\hat{i}\]and \[\hat{j}\]denote unit vectors along \[x-\]and y- directions, respectively. Which one of the following statements is wrong for the motion of particle?

    A)  Path of the particle is a circle of radius 4 meter

    B)  Acceleration vectors is along \[-\vec{R}\]

    C)  Magnitude of acceleration vector is \[\frac{{{v}^{2}}}{R}\] where v is the velocity of particle.

    D)  Magnitude of the velocity of particle is 8 meter/second

    Correct Answer: D

    Solution :

    \[\vec{R}=4\sin (2\pi t)\hat{i}+4\cos (2\pi t)\hat{j}=x\hat{i}+yj\] Now, \[{{x}^{2}}+{{y}^{2}}={{4}^{2}},\]which is equation of circle of radius R. So, the motion is uniform circular motion with speed \[V=8\pi \sqrt{2}\,m/s\]


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