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NEET Sample Paper NEET Sample Test Paper-37

  • question_answer
    For the reaction; \[2{{N}_{2}}{{O}_{5}}\to 4N{{O}_{2}}+{{O}_{2}},\]rate and rate constant are \[1.02\times {{10}^{-4}}M{{\sec }^{-1}}\]and \[3.4\times {{10}^{-5}}{{\sec }^{-1}}M\]respectively, then concentration of \[{{N}_{2}}{{O}_{5}},\]at that time will be

    A)  1.732 M

    B)  3 M

    C) \[1.02\times {{10}^{-4}}\,M\]

    D) \[3.5\times {{10}^{5}}M\]

    Correct Answer: B

    Solution :

     \[r=K[{{N}_{2}}{{O}_{5}}]\] \[\therefore \] \[[{{N}_{2}}{{O}_{5}}]=\frac{r}{K}=\frac{1.02\times {{10}^{-4}}}{3.4\times {{10}^{-5}}}=\,3\,M\]


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