A) 4:9
B) 9:4
C) 3:2
D) 2:3
Correct Answer: D
Solution :
We know kinetic energy of a particle \[K=\frac{1}{2}m{{v}^{2}}\] We can write \[K=\frac{1}{2}m{{v}^{2}}\times \left( \frac{m}{m} \right)=\frac{1}{2}\frac{{{m}^{2}}{{v}^{2}}}{m}=\frac{{{p}^{2}}}{2m}\] \[p=\sqrt{2mK}\Rightarrow \frac{{{p}_{1}}}{{{p}_{2}}}\sqrt{\frac{{{m}_{1}}}{{{m}_{2}}}=}\sqrt{\frac{4}{9}}=\frac{2}{3}\]You need to login to perform this action.
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