A) \[{{t}_{1}}>{{t}_{2}}\]
B) \[{{t}_{1}}=4{{t}_{2}}\]
C) \[{{t}_{1}}=2{{t}_{2}}\]
D) \[{{t}_{1}}={{t}_{2}}\]
Correct Answer: C
Solution :
Applying Kepler's law of area of planetary motion. The line joining the sun to the planet sweeps out equal areas in equal time interval i.e., areal velocity is constant. \[\frac{dA}{dt}=\]constant or \[\frac{{{A}_{1}}}{{{t}_{1}}}=\frac{{{A}_{2}}}{{{t}_{2}}}\Rightarrow {{t}_{1}}=\frac{{{A}_{1}}}{{{A}_{2}}}{{t}_{2}}\] Given \[{{A}_{1}}=2{{A}_{2}}\] \[\therefore \] \[{{t}_{1}}=2{{t}_{2}}\]You need to login to perform this action.
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