A) \[NaCl<LiCl<BeC{{l}_{2}}\]
B) \[BeC{{l}_{2}}<NaCl<LiCl\]
C) \[BeC{{l}_{2}}<LiCl<NaCl\]
D) \[LiCl<NaCl<BeC{{l}_{2}}\]
Correct Answer: A
Solution :
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