A) \[30g\,mo{{l}^{-1}}\]
B) \[27g\,mo{{l}^{-1}}\]
C) \[27g\,mo{{l}^{-1}}\]
D) \[~40gmo{{l}^{-1}}\]
Correct Answer: B
Solution :
We know \[d=\frac{Z\times M}{V\times {{N}_{A}}}\] \[2.72=\frac{4\times M}{6.02\times {{10}^{23}}\times {{(404\times {{10}^{-10}})}^{3}}}\] \[\Rightarrow \]\[M=27\,g\,mo{{l}^{-}}\]You need to login to perform this action.
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