A) \[2.0\times {{10}^{10}}\]
B) \[3.9\times {{10}^{15}}\]
C) \[4.0\times {{10}^{10}}\]
D) \[2.4\times {{10}^{10}}\]
Correct Answer: B
Solution :
\[{{E}^{o}}=\frac{0.059}{2}\,\log {{K}_{C}}\] \[0.46=\frac{0.059}{2}\log {{K}_{C}}\] \[\log {{K}_{C}}=15.59\]? \[\Rightarrow \]\[{{K}_{C}}=3.9\times {{10}^{15}}\]You need to login to perform this action.
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