A) Cr > Mn > Co > Fe
B) Mn > Fe > Cr > Co
C) Fe > Mn > Co > Cr
D) Co > Mn > Fe > Cr
Correct Answer: B
Solution :
\[M{{n}^{2+}}({{d}^{5}})\] gets highest stabilization due to half-filled configuration. In case of\[F{{e}^{2+}}({{d}^{6}}),\]addition of one extra electron in the subshell destabilizes it. Addition of two electrons in case of \[C{{o}^{2+}}({{d}^{7}})\]destabilizes it more.\[C{{r}^{2+}}({{d}^{4}})\]has one vacant subshell. Fe24" gets more stabilization as compared to Cr through exchange energy. So correct order is Mn > Fe > Cr > Co.You need to login to perform this action.
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