A force F acting on an object varies with distance \[x\]as shown liere. The force is in newton and x in metre. The work done by the force in moving the object from \[x=0\]to \[x=6\,m\]is
A) 4.5 J
B) 13.5 J
C) 9.0 J
D) 18.0 J
Correct Answer:
B
Solution :
Work done = Area enclosed by\[F-x\]graph \[=\frac{1}{2}\times (3+6)\times 3=13.5\,J\]