A) 20.13
B) 2.013
C) 2.198
D) 21.98
Correct Answer: D
Solution :
\[\Delta D=\frac{\Delta {{H}_{f}}}{T}=\frac{6.0}{273}=0.02198\,kJ\,{{K}^{-1}}\,mo{{l}^{-}}\] \[=0.02198\times 1000\,J{{K}^{-1}}\,mo{{l}^{-1}}\] \[=21.98\,J{{K}^{-1}}\,mo{{l}^{-1}}.\]You need to login to perform this action.
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