A) 8.0cm
B) 10.0cm
C) Any value less than 12.0 cm
D) 4.0cm
Correct Answer: B
Solution :
Let the minimum amplitude of SHM is a. Restoring force on spring, F = ka Restoring force is balanced by weight mg of block. For mass to execute simple harmonic motion of amplitude a. \[ka=mg\]or \[a=\frac{mg}{k}\] Here, \[m=2\,kg,\,k=200\,N/m,g=10\,m/{{s}^{2}}\] \[a=\frac{2\times 10}{200}=\frac{10}{100}m=\frac{10}{100}\times 100\,cm=10\,cm\] Hence, minimum amplitude of the motion should be 10 cm, so that the mass gets detached from the pan.You need to login to perform this action.
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