A) \[\text{60 }\!\!{}^\circ\!\!\text{ }\]
B) \[\text{45 }\!\!{}^\circ\!\!\text{ }\]
C) \[30{}^\circ \]
D) \[\text{90 }\!\!{}^\circ\!\!\text{ }\]
Correct Answer: A
Solution :
\[\vec{A}\times \vec{B}=AB\sin \theta \]and \[\vec{A}.\vec{B}=AB\cos \theta .\] Given, \[|\vec{A}\times \vec{B}|=\sqrt{3}(\vec{A}.\vec{B})\] \[\Rightarrow \]\[AB\sin \theta =\sqrt{3}AB\cos \theta \] \[\Rightarrow \]\[\tan \theta =\sqrt{3}\] \[\theta ={{60}^{o}}\]You need to login to perform this action.
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