A) 24 Ns
B) 20 Ns
C) 12Ns
D) 6Ns
Correct Answer: C
Solution :
\[F=\frac{dp}{dt}dp=F.dt\]or \[\int\limits_{{{p}_{i}}}^{{{p}_{f}}}{dp=\int_{{}}^{{}}{{}}}\] Change in momentum = Area under the F versus graph in that interval \[=\left( \frac{1}{2}\times 2\times 6 \right)-(2\times 3)+(4\times 3)\] \[=6-6+12=12\,Ns\]You need to login to perform this action.
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