A) \[1.3\times {{10}^{4}}g\]
B) \[1.3\times {{10}^{4}}g\]
C) \[8.05\times {{10}^{4}}g\]
D) \[2.4\times {{10}^{5}}\,g\]
Correct Answer: C
Solution :
Eq. of Al formed \[=\frac{m}{F}=\frac{it}{96500}\] \[\therefore \] \[{{m}_{Al}}=\frac{4\times {{10}^{4}}\times 6\times 60\times 60\times 27}{96500\times 3}\left( E=\frac{27}{3} \right)\] \[\therefore \]\[{{m}_{Al}}=8.05\times {{10}^{4}}g\]You need to login to perform this action.
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