A) \[2:1\]
B) \[1:16\]
C) \[4:1\]
D) \[16:1\]
Correct Answer: D
Solution :
\[H={{i}^{2}}RT={{i}^{2}}\left( \frac{\rho l}{A} \right)t\] \[=\frac{{{i}^{2}}\rho Vt}{{{A}^{2}}}\] (V = volume) \[\Rightarrow \] As, \[\rho V\] = mass, t = time and i = current (constants) \[\Rightarrow \] \[H\propto \frac{1}{{{r}^{4}}}\] \[\therefore \] \[\frac{{{H}_{1}}}{{{H}_{2}}}={{\left( \frac{{{r}_{2}}}{{{r}_{1}}} \right)}^{4}}={{\left( \frac{2}{1} \right)}^{4}}=\frac{16}{1}\]You need to login to perform this action.
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