A) \[\frac{A\,{{\varepsilon }_{0}}}{2d}\]
B) \[\frac{3A\,{{\varepsilon }_{0}}}{2d}\]
C) \[\frac{2A\,{{\varepsilon }_{0}}}{2d}\]
D) \[\frac{5A\,{{\varepsilon }_{0}}}{3d}\]
Correct Answer: D
Solution :
The equivalent circuit can be given as \[\therefore \] \[{{C}_{eq}}=C+\frac{C\times 2C}{C+2C}\] \[=C+\frac{2}{3}C=\frac{5}{3}C=\frac{5A{{\varepsilon }_{0}}}{3d}\]You need to login to perform this action.
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