A) \[0.37\,kg\]
B) \[0.37g\]
C) \[0.073g\]
D) \[0.07g\]
Correct Answer: C
Solution :
Now, number of particles in mass (m) \[N=\frac{m\times 6\times {{10}^{23}}}{222}\] \[\therefore \] \[{{10}^{16}}=\frac{0.693}{3.8\times 60\times 60}=\frac{m\times 6\times {{10}^{23}}}{222}\] \[\Rightarrow \] \[m=0.073\,g\]You need to login to perform this action.
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