A) \[\frac{27}{32}\]
B) \[\frac{32}{27}\]
C) \[\frac{4}{9}\]
D) \[\frac{9}{4}\]
Correct Answer: A
Solution :
As we know that \[\frac{1}{{{\lambda }_{3-1}}}=\left( \frac{1}{{{1}^{2}}}-\frac{1}{{{3}^{2}}} \right)=\frac{8R}{9}\] and \[\frac{1}{{{\lambda }_{2}}-1}=R\left( \frac{1}{12}-\frac{1}{{{2}^{2}}} \right)=\frac{3R}{4}\] \[\Rightarrow \] \[\frac{{{\lambda }_{3}}-1}{{{\lambda }_{2}}-1}=\frac{27}{32}\]You need to login to perform this action.
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