A) \[{{M}^{-1}}{{L}^{5}}{{T}^{-2}}\]
B) \[M{{L}^{5}}{{T}^{-2}}\]
C) \[M{{L}^{-5}}{{T}^{2}}\]
D) \[M{{L}^{-1}}{{T}^{-2}}\]
Correct Answer: B
Solution :
From the given equation, dimension of \[\frac{a}{{{V}^{2}}}=\] dimension of P \[\Rightarrow \] dimension of a = dimension of \[P{{V}^{2}}\] \[=M{{L}^{-1}}{{T}^{-2}}\times {{L}^{6}}=M{{L}^{5}}{{T}^{-2}}\]You need to login to perform this action.
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