A) \[{{N}_{2}}O\]
B) \[{{N}_{2}}{{O}_{3}}\]
C) \[{{N}_{2}}{{O}_{4}}\]
D) \[{{N}_{2}}{{O}_{5}}\]
Correct Answer: B
Solution :
Equimolar amounts of \[NO\] and \[N{{O}_{2}}\] gases at - \[{{30}^{o}}C\] give \[{{N}_{2}}{{O}_{3}}\] which is a blue liquid \[N{{O}_{(g)}}+N{{O}_{2(g)}}\xrightarrow{-{{30}^{o}}C}\underset{blue}{\mathop{{{N}_{2}}{{O}_{3(l)}}}}\,\]You need to login to perform this action.
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