A) \[5\times {{10}^{6}}\]
B) \[1.2\times {{10}^{6}}\]
C) \[1.4\times {{10}^{12}}\]
D) \[7.4\times {{10}^{12}}\]
Correct Answer: B
Solution :
\[C{{u}^{+}}+C{{u}^{+}}\xrightarrow{{}}Cu+C{{u}^{2+}}\] \[n=1\] \[{{E}^{o}}cell=\frac{0.0591}{n}\,\log \,k\] \[0.36=\frac{0.0591}{1}\,\log \,k\] \[\log \,k=6.0914\] or k = Antilog \[6.0914=1.2\times {{10}^{6}}\]You need to login to perform this action.
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