A) \[\sqrt{\frac{24}{11}g\,\,R}\]
B) \[\sqrt{\frac{22}{11}g\,\,R}\]
C) \[\sqrt{\frac{20}{11}g\,\,R}\]
D) \[\sqrt{\frac{18}{11}g\,\,R}\]
Correct Answer: C
Solution :
By the law of conservation of energy \[\frac{GMm}{R}+\frac{1}{2}m{{V}^{2}}=\frac{GMm}{10R+R}+0\] \[V=\sqrt{\frac{20}{11}\left( \frac{Gm}{R} \right)}=\sqrt{\frac{20}{11}}gR\]You need to login to perform this action.
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