A) \[1:2\]
B) \[2:1\]
C) \[1:1\]
D) \[1:4\]
Correct Answer: B
Solution :
Work done. \[W=\frac{1}{2}\,k{{x}^{2}}\] \[=\frac{1}{2}k\,{{\left( \frac{mg}{k} \right)}^{2}}...\] \[[\because \,\,F=kx=mg\]] \[\therefore \] \[W\propto \frac{1}{k}\] \[\Rightarrow \] \[\frac{{{W}_{A}}}{{{W}_{B}}}=\frac{{{K}_{B}}}{{{K}_{A}}}=2\] \[\Rightarrow \] \[{{W}_{A}}:{{W}_{B}}=2:1.\]You need to login to perform this action.
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