A) The maximum particle velocity of the second wave is twice that of first.
B) Their super position will produce a standing wave
C) Maximum particle acceleration for the second wave is eighteen times that of the first wave.
D) Their wave velocities are different
Correct Answer: C
Solution :
As, maximum particle acceleration \[({{a}_{\max }})={{w}^{2}}A\] \[\Rightarrow \] \[\frac{{{\left( {{a}_{\max }} \right)}_{2}}}{{{\left( {{a}_{\max }} \right)}_{1}}}={{\left( \frac{45\pi }{15\pi } \right)}^{2}}\frac{2A}{A}=18\]You need to login to perform this action.
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