\[{{A}_{2}}A+A\] (fast) |
\[A+{{B}_{2}}AB+B\] (slow) |
\[A+BAB\] (fast) |
A) 2
B) 1
C) \[1\frac{1}{2}\]
D) 0
Correct Answer: C
Solution :
From slow step, rate \[=K[{{B}_{2}}][A]\] \[\because \] \[{{A}_{L}}A+A\] \[{{K}_{eq}}=\frac{{{[A]}^{2}}}{[{{A}_{2}}]}\] \[[A]=\sqrt{{{K}_{eq}}[{{A}_{2}}]}=K_{eq}^{{\scriptstyle{}^{1}/{}_{2}}}\,\,A_{2}^{{\scriptstyle{}^{1}/{}_{2}}}\] rate \[K[{{B}_{2}}]\,K_{eq}^{{\scriptstyle{}^{1}/{}_{2}}}\,{{[{{A}_{2}}]}^{{\scriptstyle{}^{1}/{}_{2}}}}={{K}^{1}}{{[{{A}_{2}}]}^{{\scriptstyle{}^{1}/{}_{2}}}}[{{B}_{2}}]\] Hence, order \[=1\frac{1}{2}\]You need to login to perform this action.
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