A) \[1.0\,mm/s\]
B) \[10m/s\]
C) \[0.1\,mm/s\]
D) \[0.01\,mm/s\]
Correct Answer: C
Solution :
As \[l=neAVd\] \[\Rightarrow \] \[1.344=8.4\times {{10}^{22}}\times {{10}^{6}}\times 1.6\times {{10}^{-19}}\]\[\times 1\times {{10}^{-6}}\times Vd\] \[\therefore \] \[Vd=0.1\,mm/s\]You need to login to perform this action.
You will be redirected in
3 sec