A) \[\tan \theta =\frac{Qq}{2{{\varepsilon }_{0}}mg}\]
B) \[\tan \theta =\frac{Qq}{{{\varepsilon }_{0}}mg}\]
C) \[\cot \theta =\frac{Qq}{2{{\varepsilon }_{0}}mg}\]
D) \[\cot \theta =\frac{Qq}{{{\varepsilon }_{0}}mg}\]
Correct Answer: A
Solution :
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