A) 2 m
B) 4 m
C) zero
D) 6 m
Correct Answer: C
Solution :
We are given \[t=\sqrt{x}+3\] \[\Rightarrow \]\[\sqrt{x}=t-3\Rightarrow x={{(t-3)}^{2}}\] ?(i) Differentiating equation (i) we get velocity \[v=\frac{dx}{dt}=2(t-3)\] For the velocity of the particle will be zero. \[v=\frac{dx}{dt}=0\,\,\Rightarrow \,\,t=3\,s\] The displacement of the particle when its velocity is zero \[x={{(3-3)}^{2}}\Rightarrow x=0\]You need to login to perform this action.
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