A) \[(I)\,He<{{H}_{2}}<C{{O}_{2}}<{{O}_{2}},\]\[(II)\,C{{H}_{4}}>{{H}_{2}}>{{O}_{2}}\]
B) \[(I)\,{{O}_{2}}<He<{{H}_{2}}<C{{O}_{2}},\]\[(II)\,{{H}_{2}}>{{O}_{2}}>C{{H}_{4}}\]
C) \[(I)\,{{H}_{2}}<He<{{O}_{2}}<C{{O}_{2}},\]\[(II)C{{H}_{4}}>{{O}_{2}}>{{H}_{2}}\]
D) \[(I)\,{{H}_{2}}<{{O}_{2}}<He<C{{O}_{2}},\]\[(II)\,{{O}_{2}}>C{{H}_{4}}>{{H}_{2}}\]
Correct Answer: C
Solution :
\[C{{O}_{2}}\]is more easily liquefied than\[{{O}_{2}}\]gas. Hence of\[C{{O}_{2}}\]is more than that of \[{{O}_{2}}.\]Also \[C{{H}_{4}}\]is easily liquefied than\[{{H}_{2}}\] and He. Hence, a of \[C{{H}_{4}}\]is more than \[{{H}_{2}}\]and He. \[\begin{matrix} {} & He & {{H}_{2}} & {{O}_{2}} & C{{O}_{2}} & C{{H}_{4}} \\ (a) & 0.434 & 0.244 & 1.36 & 3.59 & 2.25 \\ \end{matrix}\begin{matrix} {} \\ \,\,\text{atom}{{\text{1}}^{2}}\,\text{mol}{{\text{e}}^{-2}} \\ \end{matrix}\] \[\begin{matrix} 0.0237 & 0.0266 & 0.0318 & 0.0427 & 0.0428 & 1\,mol{{e}^{-1}} \\ \end{matrix}\] \[\therefore \]Order of a \[C{{H}_{4}}>{{O}_{2}}>{{H}_{2}}\] \[\therefore \]Order of \[b\propto \]side and size of \[C{{O}_{2}}>{{O}_{2}}>He>{{H}_{2}}.\]
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