A) \[E{{L}^{2}}\]
B) \[E{{L}^{2}}\cos \theta \]
C) \[E{{L}^{2}}\sin \theta \]
D) 0
Correct Answer: D
Solution :
Flux of electric Field \[\vec{E}\]through any area \[\overset{\text{o}}{\mathop{\text{A}}}\,\]is defined as \[\phi =E.A\,\cos \theta \]or \[\phi =\vec{E}.\vec{A}=0\]the lines are parallel to the surface.You need to login to perform this action.
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