A) Zero
B) \[Bv\pi {{r}^{2}}/2\]and P is at higher potential
C) \[\pi rBv\]and R is at higher potential
D) 2rBv and R is at higher potential
Correct Answer: D
Solution :
The semicircular conducting ring (PQR) can be replaced with a straight rod of length 2r. Hence motional emf induced across the rodYou need to login to perform this action.
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