A) \[6.25\times {{10}^{-3}}\,mol\,{{L}^{-1}}{{s}^{-1}}\]and \[6.25\times {{10}^{-3}}\,mol\,{{L}^{-1}}{{s}^{-1}}\]
B) \[1.25\times {{10}^{-2}}mol\,{{L}^{-1}}{{s}^{-1}}\]and \[3.125\times {{10}^{-3}}\]\[mol{{L}^{-1}}{{s}^{-1}}\]
C) \[6.25\times {{10}^{-3}}mol{{L}^{-1}}{{s}^{-1}}\]and \[3.125\times {{10}^{-3}}\]\[mol\,{{L}^{-1}}{{s}^{-1}}\]
D) \[1.25\times {{10}^{-2}}mol{{L}^{-1}}{{s}^{-1}}\]and \[6.25\times {{10}^{-3}}mol\,{{L}^{-1}}{{s}^{-1}}\]
Correct Answer: B
Solution :
\[\frac{d[{{N}_{2}}{{O}_{5}}]}{dt}=\frac{1}{2}\frac{d[N{{O}_{2}}]}{dt}=\frac{2d[{{O}_{2}}]}{dt}=R\]You need to login to perform this action.
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