A) 7.0
B) 1.04
C) 12.65
D) 2.0
Correct Answer: C
Solution :
\[{{N}_{1}}{{V}_{1}}-{{N}_{2}}{{V}_{2}}=NV\] \[0.1\times 1-0.01\times 1=N\times 2\] \[[O{{H}^{-}}]={{N}_{R}}=\frac{0.09}{2}=0.045\,N\] \[pOH=-\log (0.045)=13.5\] \[\therefore \]\[pH=14-pOH=14-1.35=12.65\]You need to login to perform this action.
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