question_answer

In which of the following pairs, both the species are not isostructural?

A) \[N{{H}_{3}},P{{H}_{3}}\]

B) \[Xe{{F}_{4}},Xe{{O}_{4}}\]

C) \[SiC{{l}_{4}},PC{{l}_{4}}\]

D)  Diamond, silicon carbide

Correct Answer: B

Solution :

Hybridization of \[N{{H}_{3}}[\sigma =3,lp=1]\] \[s{{p}^{3}}\]geometry: tetrahedral (ii) Structure of\[Xe{{F}_{4}}\]is square planar.             Structure of\[Xe{{O}_{4}}\]is tetrahedral                         So \[Xe{{F}_{4}}\]and \[Xe{{O}_{4}}\]are not isostructural (iii) Structure of \[SiC{{l}_{4}}\]is tetrahedral                         Structure of \[PCl_{4}^{+}\]is tetrahedral             (iv) Both diamond and SiC are isostructural because both have tetrahedral arrangement and central atom is \[s{{p}^{3}}\]hybridised.