A) \[\frac{v}{g\mu }\]
B) \[\frac{g\mu }{v}\]
C) \[\frac{g}{v}\]
D) \[\frac{v}{g}\]
Correct Answer: A
Solution :
Block B will come to rest, if force applied to it will vanish due to frictional force acting between block B and surface, i.e., force applied = frictional force i.e., \[\mu mg=ma\,\,\Rightarrow a=\mu g\]? Now using \[v=u+at\] or \[0=v-\mu gt\Rightarrow t=\frac{v}{\mu g}\]You need to login to perform this action.
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